How do you solve $5 - ln x = 7$ $5-lnx=7$ ?

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Answer 1 · 2016-10-03T03:47:40

$x = \frac{1}{e^{2}}$ $x=1/e^2$

Start off by subtracting $5$ $5$ form both sides

$- ln x = 2$ $-lnx=2$

Now multiply both sides by negative $1$ $1$

$ln x = - 2$ $lnx=-2$

Rewrite both sides in terms of the base of the natural logarithm

$e^{ln x} = e^{- 2}$ $e^(lnx)=e^(-2)$

Using properties of logarithms and exponents we can write

$x = \frac{1}{e^{2}}$ $x=1/e^2$

How do you solve 5−lnx=75-lnx=7?