# How do you solve 5-lnx=7?

Oct 3, 2016

$x = \frac{1}{e} ^ 2$

#### Explanation:

Start off by subtracting $5$ form both sides

$- \ln x = 2$

Now multiply both sides by negative $1$

$\ln x = - 2$

Rewrite both sides in terms of the base of the natural logarithm

${e}^{\ln x} = {e}^{- 2}$

Using properties of logarithms and exponents we can write

$x = \frac{1}{e} ^ 2$