How do you solve 5-lnx=7?

1 Answer
Oct 3, 2016

x=1/e^2

Explanation:

Start off by subtracting 5 form both sides

-lnx=2

Now multiply both sides by negative 1

lnx=-2

Rewrite both sides in terms of the base of the natural logarithm

e^(lnx)=e^(-2)

Using properties of logarithms and exponents we can write

x=1/e^2