How do you solve #5( x ^ { 2} - 6) + 3= 13#?

1 Answer
Jim G.
Jul 22, 2017

#x=+-2sqrt2#

Explanation:

#"isolate " (x^2-6)#

#"subtract 3 from both sides"#

#5(x^2-6)cancel(+3)cancel(-3)=13-3#

#rArr5(x^2-6)=10#

#"divide both sides by 5"#

#(cancel(5)(x^2-6))/cancel(5)=10/5#

#rArrx^2-6=2#

#"add 6 to both sides"#

#rArrx^2=8#

#color(blue)"take the square root of both sides"#

#rArrx=+-sqrt8larr" note plus or minus"#

#rArrx=+-2sqrt2larr" simplifying radical"#

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