How do you solve # 5^x = 28#?

1 Answer
Mar 25, 2016

#x~~2.07#

Explanation:

#1#. Since the left and right sides of the equation do not have the same base, start by taking the logarithm of both sides.

#5^x=28#

#log(5^x)=log(28)#

#2#. Use the log property, #log_color(purple)b(color(red)m^color(blue)n)=color(blue)n*log_color(purple)b(color(red)m)#, to simplify the left side of the equation.

#xlog(5)=log(28)#

#3#. Solve for #x#.

#x=(log(28))/(log(5))#

#color(green)(|bar(ul(color(white)(a/a)x~~2.07color(white)(a/a)|)))#