# How do you solve #5/(y-2)=y+2#?

##### 2 Answers

#### Explanation:

First of all, we multiply both sides by

Now we have to check both of our solutions back into the original equation to make sure both are really solutions:

Now we know that

Good. Both solutions work. So the answer is

Hope this helps!

#### Explanation:

# 5/(y - 2) = y + 2#

Multiply

#5/cancel((y - 2)) × cancel((y -2)) = (y + 2) × (y -2)#

#5 = (y + 2) × (y - 2)#

#5 = y^2 - 2^2 color(white)(..)[∵ (a + b)(a - b) = a^2 - b^2)#

#5 = y^2 - 4#

Add

#5 + 4 = y^2 - 4 + 4#

#9 = y^2#

Square root on both the sides

#sqrt(9) =sqrt(y^(2))#

#color(blue)(y = +-3)#