How do you solve #-50= 10x#?

1 Answer
smendyka
Sep 16, 2017

See a solution process below:

Explanation:

Divide each side of the equation by #color(red)(10)# to solve for #x# while keeping the equation balanced:

#-50/color(red)(10) = (10x)/color(red)(10)#

#-5 = (color(red)(cancel(color(black)(10)))x)/cancel(color(red)(10))#

#-5 = x#

#x = -5#

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