How do you solve #500/(100-e^(x/2))=20#?

1 Answer
Jan 6, 2017

First, you get all of the constant terms on one side. Then you take the natural log of both sides.

Explanation:

#500 = 100−e^(x/2) * 20 ; 500 = 2000 – 20e^(x/2) #

#20e^(x/2) = 1500 ; e^(x/2) = 75#

#ln(e^(x/2)) = ln75 ; x/2 = 4.32 ; x = 8.64#