How do you solve #- 52- 3u = 8#?
1 Answer
Sep 13, 2016
Explanation:
Isolate the - 3u on the left side of the equation, while placing numeric terms on the right side.
add 52 to both sides of the equation.
#cancel(-52)cancel(+52)-3u=8+52#
#rArr-3u=60# divide both sides by - 3 to solve for u.
#(cancel(-3) u)/cancel(-3)=60/(-3)#
#rArru=-20" is the solution"#
