How do you solve #5a ^ { 2} + 7= - 60#?

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Answer 1 · 2017-03-12T14:01:40

See the entire solution process below:

First, subtract #color(red)(7)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#5a^2 + 7 - color(red)(7) = -60 - color(red)(7)#

#5a^2 + 0 = -67#

#5a^2 = -67#

Next, divide each side of the equation by #color(red)(5)# to isolate the #a^2# term while keeping the equation balanced:

#(5a^2)/color(red)(5) = -67/color(red)(5)#

#(color(red)(cancel(color(black)(5)))a^2)/cancel(color(red)(5)) = -67/5#

#a^2 = -67/5#

There is no real solution for this problem. A number squared is always positive and therefore cannot equal #-67/5#.

Or the solution is the empty or null set or #a = {O/}#