How do you solve #5csctheta-2=3# in the interval #(∞, -∞)#?

1 Answer
Jun 4, 2016

#(4n+1)pi/2, n=0, +-1, +-2, +-3,...#.

Explanation:

The given equation can be simplified to #sin theta = 1#.

So, #theta# gives the direction separating the 1st and 2nd quadrants.

In general, through both anticlockwise and clockwise rotations, this

direction is reached for

#theta=2npi+pi/2 = (4n+1)pi/2,n=0, +-1, +-2, +-3...#