Question

How do you solve `5e ^ { x } = 26`?

Answer 1

`x=ln(26/5)`

Explanation:

To isolate `x`, first start by diving both sides of the equation by `5`.

`e^x=26/5`

To undo exponentiation, use logarithms. To undo a base of `e`, use the natural logarithm `ln(x)`.

`ln(e^x)=ln(26/5)`

Note that `ln(e^x)=x`, since `ln(x)` and `e^x` are inverse functions.

`x=ln(26/5)approx1.648659...`