How do you solve #5x+12=x-4#?

1 Answer
Mar 13, 2016

#x=-4#

Explanation:

The trick to solving a simple equation as this one is, "isolation". Try to "isolate" the variable, x on one side and the numbers on the other side. Let's see how you can do this.
#5x + 12= x-4# Now why don't we subtract 12 on both sides
#5x + cancel(12) - cancel(color(red)(12))= x-4 - color(red)(12)#
What we have is now:
#5x = x-16# Well now let's bring #x# to the left side, we can do this by subtracting #x# on both sides:
#5x - color(blue)(x)= cancel(x)-16 - cancel(color(blue)(x)#
#4x = -16# we are not done we need to eliminate the #4#
Well let's divide both sides by 4:
#cancel(4)x * color(magenta)(1/cancel(4)) = -16*color(magenta)(1/4)#
And finally we have isolated #x#, so #x# is:
#x=-4#

Hope it helps. Follow this basic recipe an you will be able to solve any equation of this kind... Good Luck!