Question

How do you solve `|5x + 2| < 7`?

Answer 1

`5x+2<7 and 5x+2> -7,5x<5->x<1 and 5x > -9->x > -9/5`
`(-9/5) < x<1`

Explanation:

Use the definition of absolute value of x to solve. That is, `|x|=x if x>=0, and -x if x<0`. Then solve for x