# How do you solve 5x^2 + 7x = 6  using the quadratic formula?

Apr 1, 2017

Using the quadratic formula, $x =$ $\frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$, we get that $x = - 2 , 0.6$

#### Explanation:

Rearrange the equation so that it becomes: $5 {x}^{2} + 7 x - 6 = 0$

The quadratic formula is: $x =$ $\frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

In our equation above,
$a = 5$
$b = 7$
$c = - 6$

Plugging these values into the quadratic equation gives:

$x =$ $\frac{- 7 \pm \sqrt{{7}^{2} - 4 \left(5\right) \left(- 6\right)}}{2 \left(5\right)}$

$x =$ $\frac{- 7 \pm \sqrt{49 + 120}}{10}$

$x =$ $\frac{- 7 \pm \sqrt{169}}{10}$

$x =$ $\frac{- 7 \pm 13}{10}$

$x = - 2 , 0.6$