# How do you solve 5x^2 + x = 3 using the quadratic formula?

Mar 24, 2016

$x = \frac{- 1 \pm \sqrt{61}}{10}$

#### Explanation:

Given

$a {x}^{2} + b x + c = 0$

$\implies x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$5 {x}^{2} + x = 3 \implies 5 {x}^{2} + x - 3 = 0$

$\implies a = 5$
$\implies b = 1$
$\implies c = - 3$

$x = \frac{- 1 \pm \sqrt{{1}^{2} - 4 \cdot 5 \cdot - 3}}{2 \cdot 5}$

$x = \frac{- 1 \pm \sqrt{1 + 60}}{10}$

$x = \frac{- 1 \pm \sqrt{61}}{10}$