How do you solve #5x + 4< 3( 5x - 2)#?

1 Answer
Jun 6, 2018

Answer:

#x>1#

Explanation:

#"distribute the bracket on the right side"#

#5x+4<15x-6#

#"collect terms in x on one side and numeric values on"#
#"the other side"#

#"subtract "5x" from both sides"#

#cancel(5x)cancel(-5x)+4<15x-5x-6#

#4<10x-6#

#"add 6 to both sides"#

#4+6<10x#

#10<10x#

#"divide both sides by 10"#

#1< x" or "x>1#