How do you solve #5y + 7- 2y = 2( y + 3) + 1#?

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Answer 1 · 2018-01-16T17:43:06

#y=0#

#5y+7-2y=2(y+3)+1#

expand brackets;

#5y+7-2y=2y+6+1#

collect like terms on either side:

#3y+7 = 2y + 7#

subtract #7#:

#3y = 2y#

#0 * 3 = 0 * 2 = 0#

the only solution for #y# is #0#.