How do you solve #6-1(6x+4)\leq 9(5x+3)#?

Question

366 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-21T05:53:24

The solution is #x=-25/51#."'

Solve: #6-1(6x+4)<=9(5x+3)#
Expand both sides using the distributive property: #a(b+c)=ab+ac#.

#6-6x-4<=45x+27#

Add #6x# to both sides.

#6-4<=45x+27+6x#

Simplify.

#2<=51x+27#

Subtract #27# from both sides.

#2-27<=51x#

#-25<=51x#

Divide both sides by #51#.

#-25/51<=x#

Switch sides. This will reverse the inequality.

#x>=-25/51#

.