# How do you solve #(6^ { 2} - 2^ { 2} ) \div ( 4^ { 1} - 1^ { 2} + 1) \div ( 8+ 10)#?

##### 1 Answer

Dec 7, 2016

#### Explanation:

We then do the second set of parenthesis:

Repeat this step for the last pair of parenthesis:

Now solve:

Now simplify the fraction:

Since these two numbers both are factorable by

Therefore the simplified factored version is:

Answer: