How do you solve #-6=2/3z#?

1 Answer
May 3, 2017

Answer:

See the solution process below:

Explanation:

Multiply each side of the equation by #color(red)(3)/color(blue)(2)# to solve for #z# while keeping the equation balanced. #color(red)(3)/color(blue)(2)# is the inverse of the #z# coefficient:

#color(red)(3)/color(blue)(2) * -6 = color(red)(3)/color(blue)(2) * 2/3z#

#-18/2 = cancel(color(red)(3))/cancel(color(blue)(2)) * color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(3)))z#

#-9 = z#

#z = -9#