Question

How do you solve `-6=2/3z`?

Answer 1

See the solution process below:

Explanation:

Multiply each side of the equation by `color(red)(3)/color(blue)(2)` to solve for `z` while keeping the equation balanced. `color(red)(3)/color(blue)(2)` is the inverse of the `z` coefficient:

`color(red)(3)/color(blue)(2) * -6 = color(red)(3)/color(blue)(2) * 2/3z`

`-18/2 = cancel(color(red)(3))/cancel(color(blue)(2)) * color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(3)))z`

`-9 = z`

`z = -9`