How do you solve #6+ 2t - 4= 7t + 11- 4t#?

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Answer 1 · 2018-06-07T22:02:06

#t=-9#

We can combine the constants on the left side and the variables on the right side respectively. We get

#2t+2=3t+11#

Let's subtract #2# from both sides to get

#2t=3t+9#

Subtracting #3t# from both sides, we get

#-t=9#

Dividing both sides by #-1#, we get

#t=-9#

Hope this helps!