How do you solve #6( 2x - 7) = - 30#?

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Answer 1 · 2017-06-17T19:55:54

See a solution process below:

First, divide each side of the equation by #color(red)(6)# to eliminate the parenthesis while keeping the equation balanced:

#(6(2x - 7))/color(red)(6) = -30/color(red)(6)#

#(color(red)(cancel(color(black)(6)))(2x - 7))/cancel(color(red)(6)) = -5#

#2x - 7 = -5#

Next, add #color(red)(7)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x - 7 + color(red)(7) = -5 + color(red)(7)#

#2x - 0 = 2#

#2x = 2#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 2/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 1#

#x = 1#