How do you solve #6/(4+2w)=-2/(w-10)#?

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Answer 1 · 2017-05-27T14:55:18

#w=5.2#

#6/(4+2w)=- 2/(w-10)#

:multiplyR.H.S and L.H.S.by #(4+2w)(w-10)#

#:.(6(cancel(4+2w))(w-10))/cancel(4+2w)=(- 2(4+2w)cancel((w-10)))/cancel(w-10)#

#:.6(w-10=-2(4+2w))#

#:.6w-60=-8-4w#

#:.6w+4w=-8+60#

#:.10w=52#

#:.color(blue)(w=5.2#

substitute #color(blue)(w=5.2#

#:.6/(4+2(color(blue)5.2))=- 2/((color(blue)5.2)-10)#

#:.6/(4+10.4)=- 2/(4.8)#

#:.6/14.4=(- 2)/-4.8#

#:.color(blue)(0.416666666=0.416666666#