Question

How do you solve `-6= 9( x + 8) + 3x`?

Answer 1

After some arrangement, you can solve it easily and get `x=-13/2`

Explanation:

`-6 = 9x + 72 + 3x`

`-6 - 72 = 12x`

`-78 = 12 x`

`-78/12 = x`

`x= -13/2`

This is the solution: `x=-13/2`

Answer 2

See a solution process below:

Explanation:

First, expand the term in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

`-6 = color(red)(9)(x + 8) + 3x`

`-6 = (color(red)(9) xx x) + (color(red)(9) xx 8) + 3x`

`-6 = 9x + 72 + 3x`

Next, group and combine like terms on the right side of the equation:

`-6 = 9x + 3x + 72`

`-6 = (9 + 3)x + 72`

`-6 = 12x + 72`

Then, subtract `color(red)(72)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`-6 - color(red)(72) = 12x + 72 - color(red)(72)`

`-78 = 12x + 0`

`-78 = 12x`

Now, divide each side of the equation by `color(red)(12)` to solve for `x` while keeping the equation balanced:

`-78/color(red)(12) = (12x)/color(red)(12)`

`-(6 xx 13)/color(red)(6 xx 2) = (color(red)(cancel(color(black)(12)))x)/cancel(color(red)(12))`

`-(color(red)(cancel(color(black)(6))) xx 13)/color(red)(color(black)(cancel(color(red)(6))) xx 2) = x`

`-13/2 = x`

`x = -13/2`