How do you solve #-6\leq x + 9\leq 12#?

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Answer 1 · 2017-06-04T19:43:49

See a solution process below:

Subtract #color(red)(9)# from each segment of the system of inequalities to solve for #x# while keeping the system balanced:

#-6 - color(red)(9) <= x + 9 - color(red)(9) <= 12 - color(red)(9)#

#-15 <= x + 0 <= 3#

#-15 <= x <= 3#

Or

#x >= -15# and #x <= 3#

Or, in interval notation:

#[-15, 3]#