How do you solve #-6( n + 2) + 15= - 3n - 9#?

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Answer 1 · 2018-05-08T22:24:23

n = 4

#-6(n + 2) + 15 = -3n - 9#

I expanded the brackets:
#-6(n + 2)#
#-6 xx n# and #-6 xx 2#
#-6n - 12#

So now you have...
#-6n - 12 + 15 = -3n - 9#

Then you solve that...
#-6n - 12 + 15 = -3n - 9#

#-6n + 3 = -3n - 9#

#-6n + 3 + 3n = -9#
#-3n + 3 = -9#

#-3n = -9 - 3#
#-3n = -12#

#n = (-12)/-3# (-12 divided by -3)
#n =4#