How do you solve #6(t+4)=12#?

2 Answers
Jim G.
Oct 5, 2016

#t=-2#

Explanation:

First step is to distribute the bracket on the left side.

#6t+24=12#

subtract 24 from both sides of the equation.

#6tcancel(+24)cancel(-24)=12-24#

#rArr6t=-12#

To solve for t, divide both sides by 6.

#(cancel(6) t)/cancel(6)=-12/6#

#rArrt=-2" is the solution"#

EZ as pi
Oct 5, 2016

#t=-2#

Explanation:

#6(t+4) = 12" "larr# isolate the bracket with t.

#(cancel6(t+4))/cancel6 = 12/6" "larr#divide both sides by 6

#t+4 = 2" "larr # isolate t

#t = 2-4#

#t =-2#

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