Question

How do you solve `6^(x-3) = 2^x`?

Answer 1

`x=3 log 6/(log 6-log 2)=4.893`, nearly.

Explanation:

Equating logarithms,

`(x-3)log 6=x log 2`. Solving for x.

`x=3 log 6/(log 6-log 2)`