# How do you solve 6( x - 3) - 4( x + 1) \geq 2x - 13?

Apr 11, 2018

There is no solution

#### Explanation:

Expand and simplify.

$6 \left(x - 3\right) - 4 \left(x + 1\right) \ge q 2 x - 13$
$6 x - 18 - 4 x - 4 \ge q 2 x - 13$

$2 x - 22 \ge q 2 x - 13$

$- 9 \ge q 0$

Now this is obviously absurd so the inequality does not hold.

There is no solution for this. If you graph $y = \left(6 x - 3\right) - 4 \left(x + 1\right)$ and $y = 2 x - 13$ you can see that the two lines are parallel and never intersect and that $y = 2 x - 13$ is always greater.