How do you solve #6(x+4)=3x-2#?

Question

3605 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-27T04:37:21

#x = -8 2/3#

#6(x+4) = 3x - 2#

Use the distributive property to simplify the left side:
#6x + 24 = 3x - 2#

Subtract #color(blue)(3x)# from both sides:
#6x quadcolor(blue)(-quad3x) + 24 = 3x quadcolor(blue)(-quad3x) - 2 #

#3x + 24 = -2#

Subtract #color(blue)24# from both sides:
#3x + 24 quadcolor(blue)(-quad24) = -2 quadcolor(blue)(-24)#

#3x = -26#

#x = -8 2/3#

Hope this helps!