How do you solve #.6(y+3) = 4.8#?

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Answer 1 · 2017-06-02T23:29:34

See a solution process below:

First, divide each side of the equation by #color(red)(0.6)# to eliminate the need for parenthesis while keeping the equation balanced:

#(.6(y + 3))/color(red)(0.6) = 4.8/color(red)(0.6)#

#(color(red)(cancel(color(black)(.6)))(y + 3))/cancel(color(red)(0.6)) = 8#

#y + 3 = 8#

Now, subtract #color(red)(3)# from each side of the equation to solve for #y# while keeping the equation balanced:

#y + 3 - color(red)(3) = 8 - color(red)(3)#

#y + 0 = 5#

#y = 5#