# How do you solve 6k+3(k+2)=5k+12?

Jun 6, 2017

$k = \frac{3}{2}$

#### Explanation:

$6 k + 3 \left(k + 2\right) = 5 k + 12$

expand the parenthesis
$6 k + 3 k + 6 = 5 k + 12$
$9 k + 6 = 5 k + 12$

minus $5 k$ to both sides
$9 k + 6 - 5 k = 5 k + 12 - 5 k$
$4 k + 6 = 12$

minus $6$ to both sides
$4 k + 6 - 6 = 12 - 6$
$4 k = 6$

divide $4$ to both sides
$\frac{4 k}{4} = \frac{6}{4}$
$k = \frac{6}{4} = \frac{3}{2}$