How do you solve #6m - 6< 2( m + 6) + 1#?

1 Answer
May 17, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the right side of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:

#6m - 6 < color(red)(2)(m + 6) + 1#

#6m - 6 < (color(red)(2) * m) + (color(red)(2) * 6) + 1#

#6m - 6 < 2m + 12 + 1#

#6m - 6 < 2m + 13#

Next, add #color(red)(6)# and subtract #color(blue)(2m)# from each side of the inequality to isolate the #m# term while keeping the inequality balanced:

#-color(blue)(2m) + 6m - 6 + color(red)(6) < -color(blue)(2m) + 2m + 13 + color(red)(6)#

#(-color(blue)(2) + 6)m - 0 < 0 + 19#

#4m < 19#

Now, divide each side of the inequality by #color(red)(4)# to solve for #m# while keeping the inequality balanced:

#(4m)/color(red)(4) < 19/color(red)(4)#

#(color(red)(cancel(color(black)(4)))m)/cancel(color(red)(4)) < 19/4#

#m < 19/4#