# How do you solve 6n^2-18n-18=6  by factoring?

Aug 17, 2015

Let's start by dividing everything by $6$

#### Explanation:

$\to {n}^{2} - 3 n - 3 = 1$

Now subtract $1$ on both sides to get an $= 0$ equation
$\to {n}^{2} - 3 n - 4 = 0$

Now we factor, by finding factors of $- 4$ that add up to $- 3$
These are $- 4 \mathmr{and} + 1$
$\to \left(n - 4\right) \left(n + 1\right) = 0$

Two solutions:
$\left(n - 4\right) = 0 \to n = 4 \mathmr{and} \left(n + 1\right) = 0 \to n = - 1$