How do you solve #6q = 6( 4q + 1)#?

Question

1026 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-08T23:01:50

#q = -1/3#

Step 1) Expand the terms in parenthesis.
Step 2) Solve for #q# while keeping the equation balanced

#6q = 24q + 6#

#6q - 6q - 6 = 24q + 6 - 6q - 6#

#-6 = 24q - 6q#

#-6 = 18q#

#-6/18 = (18q)/18#

#q = -1/3#