How do you solve #6t ^ { 2} = - 4t#?

3 Answers
Apr 5, 2018

Answer:

#t=0 or t=-2/3#

Explanation:

#6t^2+4t=0#

#2t(3t+2)#=0

#2t=0 or 3t=-2#

#t=0 or-2/3#

Apr 5, 2018

Answer:

#t=0# and #t=-2/3#

Explanation:

Add #-4t# to both sides:

#6t^2+4t=cancel(-4t+4t)#

#6t^2+4t=0#

We can then factor out #2t#:

#2t(3t+2)=0#

We can then use the zero factor principle to know that this equation holds either when #2t=0# or when #3t+2=0#. This gives us two different solutions:

#2t=0->t=0#

#3t+2=0->-2/3#

These are the solutions to the equation.

Apr 5, 2018

Answer:

The answer is : -2/3

Explanation:

Hello there!!

Let me explain how to do this.....
It is very simple.

Take,

#6t^2 = -4t#

Now " t " is cancelled out on both sides,

#6t = -4#

then,
#t = -4 / 6#

Now your answer is ready that is:

#t = -2/3# or #t = 0#

Hope you like my answer.......