How do you solve #6x + 12= - 84- 10x#?

1 Answer
Jan 15, 2018

See a solution process below:

Explanation:

First, subtract #color(red)(12)# and add #color(blue)(10x)# to each side of the equation to isolate the #x# term while keeping the inequality balanced:

#6x + color(blue)(10x) + 12 - color(red)(12) = -84 - color(red)(12) - 10x + color(blue)(10x)#

#(6 + color(blue)(10))x + 0 = -96 - 0#

#16x = -96#

Now, divide each side of the equation by #color(red)(16)# to solve for #x# while keeping the equation balanced:

#(16x)/color(red)(16) = -96/color(red)(16)#

#(color(red)(cancel(color(black)(16)))x)/cancel(color(red)(16)) = -6#

#x = -6#