How do you solve #-6x + 15= - 3#?

1 Answer
Jim G.
Oct 20, 2016

#x=3#

Explanation:

Leave the term in x where it is on the left side of the equation and collect numeric values on the right side.

subtract 15 from both sides.

#-6xcancel(+15)cancel(-15)=-3-15#

#rArr-6x=-18#

To solve for x, divide both sides by - 6.

#(cancel(-6) x)/cancel(-6)=(-18)/(-6)#

#rArrx=3" is the solution"#

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