How do you solve #6x^2 + 11x + 4# using the quadratic formula?

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Answer 1 · 2016-03-08T15:01:10

The solutions are:
#x=-1/2 #

#x=-4/3 #

#6x^2 +11x +4=0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:
#a=6, b=11, c=4#

The Discriminant is given by:

#Delta=b^2-4*a*c#

# = (11)^2-(4*6 * 4)#

# = 121-96=25#

The solutions are found using the formula:

#x=(-b+-sqrtDelta)/(2*a)#

#x = ((-11)+-sqrt(25))/(2*6) = (-11+-5)/12#

#x=(-11+5)/12 =-6/12=-1/2 #

#x=(-11-5)/12 =-16/12=-4/3 #