How do you solve #6x^2 + 2x = 104#?
Apply the quadratic formula.
Simplify to get
Simplify even more to get
Use the new Transforming Method (Socratic, Google Search).
Proceeding. Find the 2 real roots of y', then, divide them by a = 3.
Find 2 real roots, that have opposite signs (ac < 0), knowing their sum (-b = -1) and their product (ac = - 156). They are 12 and - 13.
Back to y, the 2 real roots of y are: