# How do you solve #6x^2-5x+3=0#?

##### 1 Answer

May 23, 2015

y = 6x^2 - 5x + 3 = 0

D = d^2 = b^2 - 4ac = 25 - 72 = -47 < 0. There are no real roots, meaning the parabola graph doesn't intersect the x-axis.

There are 2 complex roots: