# How do you solve #6x^2+7x+2=0#?

##### 2 Answers

Dec 11, 2016

#### Answer:

#### Explanation:

You need to factor this quadratic by playing with multipliers for 6 (1x6, 2x3, 3x2, 6x1) and multipliers for 2 (1x2, 2x1):

Now we can solve each term for

and

Dec 11, 2016

#### Answer:

#### Explanation:

Given:

#6x^2+7x+2 = 0#

Use an AC method:

Find a pair of factors of

The pair

Use this pair to split the middle term and factor by grouping:

#0 = 6x^2+7x+2#

#color(white)(0) = 6x^2+4x+3x+2#

#color(white)(0) = (6x^2+4x)+(3x+2)#

#color(white)(0) = 2x(3x+2)+1(3x+2)#

#color(white)(0) = (2x+1)(3x+2)#

Hence zeros: