How do you solve #6x^2 + 8x = 14#?

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Answer 1 · 2015-09-09T12:52:00

This equation has 2 real solutions: #x_1=-2 1/3# and #x_2=1#

Before further calculations you have to move #14# to the left:

#6x^2+8x-14=0#

Now you can divide both sides by #2#:

#3x^2+4x-7=0#

Now you can calculate the discriminant:

#Delta=4^2-4*3*(-7)=16+84=100#
#sqrt(Delta)=10#

#x_1=(-b-sqrt(Delta))/(2*a)=(-4-10)/(2*3)=-14/6=-2 1/3#

#x_2=(-b+sqrt(Delta))/(2*a)=(-4+10)/(2*3)=6/6=1#