# How do you solve 6x-3y=-5 and x-2/3y=-1?

Jul 11, 2018

$x = - \frac{19}{3} , y = - 11$

#### Explanation:

Solving the second equation for $x$ we get

$x = 1 + \frac{2}{3} y$
substituting this (for $x$) in the first equation

$6 \left(1 + \frac{2}{3} y\right) - 3 y = - 5$
expanding

$6 + 4 y - 3 y = - 5$

so $y = - 11$
and

$x = 1 + \frac{2}{3} \cdot \left(- 11\right) = \frac{3 - 22}{3} = - \frac{19}{3}$