How do you solve #6x + 8> 2x - 12#?

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Answer 1 · 2016-11-19T15:31:07

#x > -5#

Perform the necessary mathematics to isolate and solve for #x# while keeping the inequality balanced:

First, subtract #8# from each side of the inequality:

#6x + 8 - 8 > 2x - 12 - 8#

#6x + 0 > 2x - 20#

#6x > 2x - 20#

Next, subtract #2x# from each side of the equation:

#6x - 2x > 2x - 20 - 2x#

#(6 - 2)x > 0 - 20#

#4x > -20#

Finally, divide each side of the equation by #4#:

#(4x)/4 > (-20)/4#

#(4/4)x > -5#

#1x > -5#

#x > -5#