# How do you solve 6x=-x²-8?

Jan 24, 2017

$x = - 2$ or $x = - 4$

#### Explanation:

$6 x = - {x}^{2} - 8$

Add ${x}^{2} + 8$ to both sides.

${x}^{2} + 6 x + 8 = 0$

Factorise.

${x}^{2} + 4 x + 2 x + 8 = 0$

$x \left(x + 4\right) + 2 \left(x + 4\right) = 0$

$\left(x + 2\right) \left(x + 4\right) = 0$

$x + 2 = 0$ or $x + 4 = 0$

$x = - 2$ or $x = - 4$