How do you solve #6z+14+5z=80#?

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Answer 1 · 2017-10-05T19:32:25

See a solution process below:

First, group and combine like terms on the left side of the equation:

#6z + 5z + 14 = 80#

#(6 + 5)z + 14 = 80#

#11z + 14 = 80#

Next, subtract #color(red)(14)# from each side of the equation to isolate the #z# term while keeping the equation balanced:

#11z + 14 - color(red)(14) = 80 - color(red)(14)#

#11z + 0 = 66#

#11z = 66#

Now, divide each side of the equation by #color(red)(11)# to solve for #z# while keeping the equation balanced:

#(11z)/color(red)(11) = 66/color(red)(11)#

#(color(red)(cancel(color(black)(11)))z)/cancel(color(red)(11)) = 6#

#z = 6#