How do you solve #7^ { 2} + 3( \sqrt { 16} - 4)#?

1 Answer
Mar 11, 2018

The result is #49#.

Explanation:

Use this property of radicals:

# color(red)sqrt(color(black)x^color(red)2)=x #

Now here's the actual problem:

# color(white)=7^2+3(sqrt16-4) #

# =7^2+3(sqrt(4*4)-4) #

# =7^2+3(sqrt(4^2)-4) #

# =7^2+3(4-4) #

# =7^2+3(0) #

# =7^2color(red)cancelcolor(black)(+3(0)) #

# =7^2 #

# =7*7 #

# =49 #