How do you solve #7+ 2u = - 1#?

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Answer 1 · 2018-01-27T17:05:17

See a solution process below:

First, subtract #color(red)(7)# from each side of the equation to isolate the #u# term while keeping the equation balanced:

#7 - color(red)(7) + 2u = -1 - color(red)(7)#

#0 + 2u = -8#

#2u = -8#

Now, divide each side of the equation by #1# to solve for #u# while keeping the equation balanced:

#(2u)/color(red)(2) = -8/color(red)(2)#

#(color(red)(cancel(color(black)(2)))u)/cancel(color(red)(2)) = -4#

#u = -4#