Question

How do you solve `7^(2x-1) = 343`?

Answer 1

`x=2`

Explanation:

We will use the following properties of logarithms:

• `log_a(a) = 1`
• `log(a^x)=xlog(a)`

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`7^(2x-1) = 343=7^3`

`log_7(7^(2x-1))=log_7(7^3)`

`(2x-1)log_7(7) = 3log_7(7)`

`2x-1 = 3`

`2x = 4`

`x = 2`