How do you solve #7/(2x-8)=3/(x-6)#?

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Answer 1 · 2016-08-20T07:14:21

#x = 18#

Students often find algebra involving fractions difficult.

In this case there is one fraction term on each side of the equation.

This means we may cross-multiply which will get rid of the denominators.

Multiply to have the bigger #x#-term, positive on the left.

#color(red)(7)/color(blue)((2x-8))=color(blue)(3)/color(red)((x-6))#

#color(red)(7xx(x-6) = color(blue)(3xx(2x-8))#

#7x-42 = 6x-24#

#7x -6x = 42-24#

#x = 18#
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Equations with more than one fraction on either side are dealt with in a different way.